(5x+1)(3x^2-14x-5)=0

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Solution for (5x+1)(3x^2-14x-5)=0 equation: 


Simplifying
(5x + 1)(3x2 + -14x + -5) = 0

Reorder the terms:
(1 + 5x)(3x2 + -14x + -5) = 0

Reorder the terms:
(1 + 5x)(-5 + -14x + 3x2) = 0

Multiply (1 + 5x) * (-5 + -14x + 3x2)
(1(-5 + -14x + 3x2) + 5x * (-5 + -14x + 3x2)) = 0
((-5 * 1 + -14x * 1 + 3x2 * 1) + 5x * (-5 + -14x + 3x2)) = 0
((-5 + -14x + 3x2) + 5x * (-5 + -14x + 3x2)) = 0
(-5 + -14x + 3x2 + (-5 * 5x + -14x * 5x + 3x2 * 5x)) = 0
(-5 + -14x + 3x2 + (-25x + -70x2 + 15x3)) = 0

Reorder the terms:
(-5 + -14x + -25x + 3x2 + -70x2 + 15x3) = 0

Combine like terms: -14x + -25x = -39x
(-5 + -39x + 3x2 + -70x2 + 15x3) = 0

Combine like terms: 3x2 + -70x2 = -67x2
(-5 + -39x + -67x2 + 15x3) = 0

Solving
-5 + -39x + -67x2 + 15x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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